+21hi guys
Was wondering if you can help me.
For my scripts i usually use below for the currently logged in user
ls -l /dev/console | cut -d " " -f4
this returns tkimpton@rufusleonard.hq
Im trying to work out how to strip out @rufusleonard.hq so i am left with tkimpton.
Any ideas?
Best answer by mm2270
Do you get a better result with the following?-
/usr/bin/who | awk '/console/{ print $1 }'If not, you can use your command and send it through another cut like this-
| cut -d@ -f1That should leave you with everything from before the @ symbol, meaning "tkimpton'
+24Do you get a better result with the following?-
/usr/bin/who | awk '/console/{ print $1 }'If not, you can use your command and send it through another cut like this-
| cut -d@ -f1That should leave you with everything from before the @ symbol, meaning "tkimpton'
+21OMG wow that if friggin awesome.
Thank you very much
went on a bender last night and my brain has b een hitting a brick wall ;)
+18/dev/console does seem to be a bit more reliable, sometimes when logging out one user and logging in a new one who on the console can produce less than consistent results in my experience anyway...
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