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Script to find folder doesn't find folder.

  • December 19, 2012
  • 1 reply
  • 0 views
C
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Developed a quick script to do a simple task, remove the iMovie (previous version) folder. While I was thinking of how to do this, I thought... "Why don't I make a script that could handle any folder path", so I did. But now it won't recognize the "(previous version)" folder, thought it appears that it does see the path properly. Here's the script...

#!/bin/bash

## Simple script to remove a folder passed to it.

if [[ $4 ]]; then
    if [[ -d $4 ]]; then
        echo "Directory found at... " $4
        ## rm -fdrv $4
    else
        echo "No Directory found at ... " $4
    fi
else
    echo "No Variable in Slot 4"
fi

and the path, with spaces and specials escaped... /Applications/iMovie (previous version).localized)

But no matter how I put the folder path in, it comes back with "no's".

No Directory found at ... /Applications/iMovie (previous version).localized
No Directory found at ... /Applications/iMovie (previous version)
No Directory found at ... /Applications/iMovie (previous version)

But if I pass it just the applications, or any other standard folder it works. It works if I pull it out of Casper and change the variables to $1. Is Casper doing something that causes the to break?

Anybody see something I might be missing?

    1 reply

    S
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    • Sonic84
    • Valued Contributor
    • 139 replies
    • December 20, 2012

    try putting the path in quotations:

    bash$ /Users/test/Desktop/test.sh 1 2 3 "/Applications/iMovie (previous version).localized"
    Directory found at... /Applications/iMovie (previous version).localized
    echo'd command: rm -fdrv /Applications/iMovie (previous version).localized

    if spaces/specials are bashing your script, you can also put the placeholders in quotes:

    #!/bin/bash

## Simple script to remove a folder passed to it.

if [[ "$4" ]]; then
    if [[ -d "$4" ]]; then
        echo "Directory found at..." "$4"
        echo "echo'd command: rm -fdrv "$4""
    else
        echo "No Directory found at ..." "$4"
    fi
else
    echo "No Variable in Slot 4"
fi

    Hope this helps!

    Reply


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